N006-E2 Tier 1 · Foundations · easy analytics · Streamhub

Return the name and current plan of every user on either the `starter` or `free` plan

Part of Boolean Logic in WHERE (AND, OR, NOT) in SQL

The problem

Streamhub's growth team is running an upsell campaign targeting users on entry-level plans.

Write a query to return the name and current plan of every user on either the starter or free plan.

Assumptions:

  • The users table contains every account on the Streamhub platform.
  • The plan column records each user's current subscription tier as one of free, starter, pro, or enterprise.

Output:

  • One row per qualifying user, with columns name and plan.
Schema · analytics 5 tables
users
id integer
name text
email text
country text
plan text
signed_up_at timestamptz
is_active boolean
conversions
id integer
user_id integer
converted_at timestamptz
plan text
amount numeric
sessions
id integer
user_id integer
started_at timestamptz
ended_at? timestamptz
event_count integer
events
id integer
user_id integer
session_id? integer
event_type text
occurred_at timestamptz
properties? jsonb
periods
id integer
name text
start_month integer
end_month integer

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Solution query
SELECT
  name,
  plan
FROM
  users
WHERE
  plan = 'starter'
  OR plan = 'free'

The shape

Two equality checks joined by OR — a row qualifies for the upsell campaign when its plan matches either of the entry-level tiers.

Clause by clause

  • SELECT name, plan names the two columns the growth team needs on the audience list: who the user is, and which plan they're sitting on. Returning plan alongside name makes the result self-describing — every row carries the reason it was included.
  • FROM users reads the users table. Every account on the platform lives here, and the filter narrows the population from there.
  • WHERE plan = 'starter' OR plan = 'free' is the membership test. OR is satisfied when at least one side is true, so a starter user passes (the first condition is true), a free user passes (the second condition is true), and a pro or enterprise user is dropped because neither side matches.

Why OR and not AND

The two conditions compare the same column to different values. A single row's plan can only ever equal one of them at a time, so writing plan = 'starter' AND plan = 'free' is asking for a value that is simultaneously two different strings. That's impossible, so the AND form would return zero rows. OR is the correct connective whenever a row qualifies by matching any one of several values on the same column.

You practiced using OR to accept rows that match any one of several discrete values. This is the recurring shape of a membership filter — the row qualifies if it falls into any of the listed buckets.

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