N041-M3 Tier 3 · Intermediate · medium ecommerce · Brightlane

Return each customer's ID, order count, total spend, and the average individual order amount across every order

Part of Temp Tables and CREATE TABLE AS SELECT in SQL

The problem

Brightlane's customer analysis pipeline materializes each customer's order count and total spend alongside the platform-wide average individual order amount for benchmarking. The temp table feeds multiple comparative reports in the same session.

Write a query to return each customer's ID, order count, total spend, and the average individual order amount across every order.

Assumptions:

  • A customer's order count is the number of orders linked to that customer_id. A customer's total spend is the combined total_amount across those orders.
  • The platform-wide average is the average of total_amount across every order in the table. The same value should appear on every output row.
  • Every customer with at least one order should appear once.

Output:

  • One row per customer, with columns customer_id, order_count, total_spent, and overall_avg.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

Run previews · Check grades

Write a query, then run it to see results here.

Worked solution Try it yourself first
Solution query
SELECT
  customer_id,
  COUNT(*) AS order_count,
  SUM(total_amount) AS total_spent,
  (
    SELECT
      AVG(total_amount)
    FROM
      orders
  ) AS overall_avg
FROM
  orders
GROUP BY
  customer_id

The shape

The per-customer aggregation runs in the main SELECT, and a scalar subquery in the SELECT list provides the platform-wide average. The scalar subquery returns exactly one value, which is then broadcast onto every output row by the engine. So each customer's row carries its own metrics alongside a benchmark that is identical across the whole result.

Clause by clause

  • SELECT customer_id, COUNT(*) AS order_count, SUM(total_amount) AS total_spent returns the three per-customer columns. GROUP BY customer_id further down makes these one-row-per-customer aggregates.
  • (SELECT AVG(total_amount) FROM orders) AS overall_avg is the scalar subquery. It runs independently of the outer grouping, scans the entire orders table once, and returns the single number 633.62865. Because the subquery returns one row with one column, PostgreSQL treats it as a constant expression in the outer SELECT and the same value lands on every output row.
  • FROM orders reads the orders table for the outer aggregation.
  • GROUP BY customer_id partitions the rows by customer so the COUNT(*) and SUM(total_amount) are per-customer.

Why a scalar subquery and not a separate query

Producing the benchmark inline keeps the materialization a single CTAS body. The downstream reports want the per-customer metrics and the platform average side by side; if the benchmark were computed in a separate query, the temp table would have to be assembled in two steps. The scalar subquery delivers the constant in one statement, and the result is a single relation already in the shape the reports need.

The trap

The scalar subquery looks like it should run once per row because it sits inside the SELECT list, but it does not depend on any outer column. PostgreSQL recognises this and evaluates it once for the entire query, caches the value, and reuses it for every row. The pattern is safe and cheap precisely because the inner SELECT is uncorrelated.

You practiced pairing a per-customer aggregation with a scalar subquery for a benchmark value — every row sees its own per-customer metrics plus the same platform-wide average.

How you actually get good at SQL

Reading explains SQL. Writing it, over and over with instant feedback, is what makes you fluent.

That's the whole SQLMaxx loop: 600+ real problems, instant AI feedback, mastery you can actually see, and spaced review that won't let you forget.

A stack of SQL practice problem cards, the top card showing an employees table.
615 problems · 66 concepts

Real problems. Not toy examples.

615 hand-built problems spanning all 66 concepts, from basic SELECTs to window functions, built on real schemas and real business questions, the kind you'll actually get asked on the job. Enough reps to make SQL automatic.

A retro computer showing a SQL query marked correct with a green checkmark.
Instant AI feedback

Write a query. Know if it's right in one second.

No copying an answer and hoping it clicked. The AI grader checks your real query against real data, catches exactly what's wrong, and explains the fix in plain English, like a senior analyst reading over your shoulder on every problem.

A circular mastery progress dial filling from blue to green, the SQLMaxx diamond at its center.
Mastery tracking

Stop guessing whether you actually know it.

SQLMaxx tracks every concept and shows you what you've mastered and what's still shaky. Your skills fill in one concept at a time, so 'I think I get joins' becomes something you can prove.

A SQL query editor circled by a blue return arrow with a clock, scheduled to come back for review.
Spaced review

Learn it once. Keep it for good.

Most of what you learn this week fades by next week. So when a concept comes due for review, SQLMaxx hands you a fresh problem to solve from a blank editor, not a flashcard to re-read. A research-backed spaced-repetition algorithm (FSRS) times each return for right before you'd forget, so your SQL is still there months later, when the interview or the job actually needs it.

Practice, feedback, mastery, review. That's the loop that turns reading into real skill.

Start free

No account, no credit card. Start solving in under a minute.