N030-E3 Tier 3 · Intermediate · easy analytics · Streamhub

Return each user's ID and the number of sessions they have recorded

Part of Common Table Expressions (CTEs) in SQL

The problem

Streamhub's product analytics team tracks how frequently users engage with the platform.

Write a query to return each user's ID and the number of sessions they have recorded.

Assumptions:

  • The sessions table has one row per session with a user_id.
  • Each user with at least one session should appear once in the report.

Output:

  • One row per user, with columns user_id and session_count.
Schema · analytics 5 tables
users
id integer
name text
email text
country text
plan text
signed_up_at timestamptz
is_active boolean
conversions
id integer
user_id integer
converted_at timestamptz
plan text
amount numeric
sessions
id integer
user_id integer
started_at timestamptz
ended_at? timestamptz
event_count integer
events
id integer
user_id integer
session_id? integer
event_type text
occurred_at timestamptz
properties? jsonb
periods
id integer
name text
start_month integer
end_month integer

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Worked solution Try it yourself first
Solution query
WITH
  user_sessions AS (
    SELECT
      user_id,
      COUNT(*) AS session_count
    FROM
      sessions
    GROUP BY
      user_id
  )
SELECT
  user_id,
  session_count
FROM
  user_sessions

The shape

A single WITH layer aggregates sessions by user_id, and the main query reads the per-user count straight out of it. The layer's name, user_sessions, behaves like a table reference in the main FROM.

Clause by clause

  • The WITH clause defines user_sessions:
WITH user_sessions AS (
  SELECT user_id, COUNT(*) AS session_count
  FROM sessions
  GROUP BY user_id
)

GROUP BY user_id partitions sessions into one bucket per user, and COUNT(*) counts the rows in each bucket. The result is one row per user with their session count: user 1 ends up with 9, user 14 with 4, user 5 with 1, and so on across every user who has at least one recorded session.

  • SELECT user_id, session_count FROM user_sessions is the main query. It reads from the named layer like any other table source and returns both of its columns. No additional logic runs in the main query; the work already happened inside the layer.

You practiced naming a per-user breakdown in a WITH layer that the main query reads from.

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