N055-M2 Tier 4 · Advanced · medium analytics · Streamhub

Return each date from March 1, 2024 through March 7, 2024 alongside the number of purchase `events` recorded on that date

Part of Date Spine Construction and Zero-Fill Patterns in SQL

The problem

Scenario: Streamhub's campaign analytics dashboard tracks daily purchase activity for the first week of March 2024 to evaluate a recent promotion's reach.

Task: Write a query to return each date from March 1, 2024 through March 7, 2024 alongside the number of purchase events recorded on that date.

Assumptions:

  • The events table holds one row per recorded event, with the timestamp stored in occurred_at and the kind of activity stored in event_type.
  • A purchase event has event_type equal to 'purchase'.
  • Some dates in the range have no recorded purchase events; those dates must still appear in the result with a count of zero.

Output:

  • One row per date in the range, including dates with no purchase events.
  • Columns in this order: day, purchase_count.
  • Sorted by day ascending.
Schema · analytics 5 tables
users
id integer
name text
email text
country text
plan text
signed_up_at timestamptz
is_active boolean
conversions
id integer
user_id integer
converted_at timestamptz
plan text
amount numeric
sessions
id integer
user_id integer
started_at timestamptz
ended_at? timestamptz
event_count integer
events
id integer
user_id integer
session_id? integer
event_type text
occurred_at timestamptz
properties? jsonb
periods
id integer
name text
start_month integer
end_month integer

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Solution query
WITH
  spine AS (
    SELECT
      GENERATE_SERIES('2024-03-01'::date, '2024-03-07'::date, '1 day'::INTERVAL)::date AS DAY
  )
SELECT
  s.day,
  COUNT(p.id) AS purchase_count
FROM
  spine s
  LEFT JOIN (
    SELECT
      id,
      occurred_at
    FROM
      events
    WHERE
      event_type = 'purchase'
  ) AS p ON p.occurred_at::date = s.day
GROUP BY
  s.day
ORDER BY
  s.day

The shape

The count has to be restricted to purchase events but the spine still has to produce all seven days, so the event_type filter is pushed into a derived table on the right side of the LEFT JOIN. Filtering inside the subquery preserves the join's outer-ness; filtering in the outer WHERE would destroy it.

Clause by clause

  • WITH spine AS (SELECT generate_series('2024-03-01'::date, '2024-03-07'::date, '1 day'::interval)::date AS day) builds the seven-day backbone for the first week of March.
  • The derived table (SELECT id, occurred_at FROM events WHERE event_type = 'purchase') AS p pre-filters the fact rows down to purchase events only, leaving every other row out of the join input entirely.
  • SELECT s.day, COUNT(p.id) AS purchase_count returns the spine's date and the count of matched purchase events. COUNT(p.id) ignores nulls, so days with no purchases report zero.
  • FROM spine s LEFT JOIN ... AS p ON p.occurred_at::date = s.day attaches each purchase to its day. The LEFT JOIN keeps every spine row whether or not a purchase matches.
  • GROUP BY s.day collapses the joined rows back to one row per spine date.
  • ORDER BY s.day returns the seven dates in calendar order.

Why this and not a WHERE event_type = 'purchase' after the join

Filtering on the right table of a LEFT JOIN in the outer WHERE silently converts it to an inner join. The rule is positional: WHERE p.event_type = 'purchase' rejects any row where p.event_type is anything other than the literal 'purchase' — and an unmatched spine row carries p.event_type = NULL, which fails that equality check. Every zero-purchase day drops out. Pushing the filter into the derived table fixes this by restricting the right side before the join sees it, so the unmatched-spine rows survive intact.

The trap

The two filters look equivalent on a whiteboard — both restrict to purchases. They behave the same on an inner join. On a LEFT JOIN they don't: the outer-WHERE form quietly drops the zero rows the spine pattern exists to keep. Whenever you're filtering the right side of a left join, put the filter inside a derived table or move it into the ON clause.

You practiced restricting the right side of a left-join to a category-specific subset so the spine still produces one row per day, with zero on days where no purchases occurred.

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