N026-E1 Tier 2 · Core SQL · easy ecommerce · Brightlane

Return the customer ID and total order count for every customer who has placed **more than three** orders

Part of Derived Tables (Subqueries in FROM) in SQL

The problem

Brightlane's CRM team is building a high-value customer list and needs to identify buyers with substantial order history.

Write a query to return the customer ID and total order count for every customer who has placed more than three orders.

Assumptions:

  • The orders table contains every order Brightlane has processed.
  • The threshold (> 3) applies to the per-customer count.
  • Each customer's order count is computed first, then the per-customer counts are narrowed to those above the threshold.

Output:

  • One row per qualifying customer, with columns customer_id and order_count.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

Run previews · Check grades

Write a query, then run it to see results here.

Worked solution Try it yourself first
Solution query
SELECT
  customer_id,
  order_count
FROM
  (
    SELECT
      customer_id,
      COUNT(*) AS order_count
    FROM
      orders
    GROUP BY
      customer_id
  ) AS customer_orders
WHERE
  order_count > 3

The shape

The inner query counts orders per customer and the outer query filters that result down to customers with more than three. The derived table is what lets WHERE reach a value — the per-customer count — that doesn't exist until after the grouping has run.

Clause by clause

  • The inner block computes one row per customer with their order count:
SELECT customer_id, COUNT(*) AS order_count
FROM orders
GROUP BY customer_id
  • FROM (...) AS customer_orders wraps that result as a derived table. The alias customer_orders is mandatory — drop it and PostgreSQL raises a syntax error before the query runs.
  • WHERE order_count > 3 filters the derived table's rows. order_count is a real column at this layer, so a plain WHERE comparison works the way it would against any table.
  • SELECT customer_id, order_count returns the two columns the CRM team's high-value list needs. The outer query can only see columns the inner SELECT exposed.

You practiced wrapping an aggregate query as a derived table so the outer query can filter on the aggregate result with WHERE. The recurring shape: any time aggregation produces a value that needs to be filtered, joined, or further aggregated, a derived table makes that second pass possible.

How you actually get good at SQL

Reading explains SQL. Writing it, over and over with instant feedback, is what makes you fluent.

That's the whole SQLMaxx loop: 600+ real problems, instant AI feedback, mastery you can actually see, and spaced review that won't let you forget.

A stack of SQL practice problem cards, the top card showing an employees table.
615 problems · 66 concepts

Real problems. Not toy examples.

615 hand-built problems spanning all 66 concepts, from basic SELECTs to window functions, built on real schemas and real business questions, the kind you'll actually get asked on the job. Enough reps to make SQL automatic.

A retro computer showing a SQL query marked correct with a green checkmark.
Instant AI feedback

Write a query. Know if it's right in one second.

No copying an answer and hoping it clicked. The AI grader checks your real query against real data, catches exactly what's wrong, and explains the fix in plain English, like a senior analyst reading over your shoulder on every problem.

A circular mastery progress dial filling from blue to green, the SQLMaxx diamond at its center.
Mastery tracking

Stop guessing whether you actually know it.

SQLMaxx tracks every concept and shows you what you've mastered and what's still shaky. Your skills fill in one concept at a time, so 'I think I get joins' becomes something you can prove.

A SQL query editor circled by a blue return arrow with a clock, scheduled to come back for review.
Spaced review

Learn it once. Keep it for good.

Most of what you learn this week fades by next week. So when a concept comes due for review, SQLMaxx hands you a fresh problem to solve from a blank editor, not a flashcard to re-read. A research-backed spaced-repetition algorithm (FSRS) times each return for right before you'd forget, so your SQL is still there months later, when the interview or the job actually needs it.

Practice, feedback, mastery, review. That's the loop that turns reading into real skill.

Start free

No account, no credit card. Start solving in under a minute.