N010-M1 Tier 1 · Foundations · medium ecommerce · Brightlane

Return each customer ID that appears in the orders data, with no duplicates

Part of DISTINCT in SQL

The problem

Brightlane's sales team is identifying active buyers for a loyalty campaign and wants to know which customers have placed at least one order.

Write a query to return each customer ID that appears in the orders data, with no duplicates.

Assumptions:

  • The orders table contains every order Brightlane has processed.
  • The customer_id column links each order to the customer who placed it; customers with many orders appear many times.

Output:

  • One row per customer who has placed at least one order, with a single column customer_id.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

Run previews · Check grades

Write a query, then run it to see results here.

Worked solution Try it yourself first
Solution query
SELECT DISTINCT
  customer_id
FROM
  orders

The shape

DISTINCT customer_id turns the orders table — which has one row per order — into a presence-list of buyers, one row per customer who has placed at least one order. A customer with twelve orders shows up once; a customer with one shows up once; a customer with zero doesn't show up at all.

Clause by clause

  • SELECT DISTINCT customer_id returns the unique customer_id values present in whatever rows FROM hands up. Every order contributes its customer_id to the candidate set, and the deduplication runs across that set to produce one row per buyer.
  • FROM orders is the row source. Critically, this is the transactional table — the orders themselves — not the customers table. That asymmetry is what makes the result a presence-list rather than a customer roster.

Why this and not SELECT customer_id FROM customers

Reading from customers would give back every customer Brightlane has on file, including the ones who have never placed an order. The loyalty campaign is targeting active buyers, not signups. The presence semantics come from reading the orders table — being in the result means having a row in orders, which by definition means having placed at least one order.

This is the everyday pattern behind cohort-building and audience-derivation: read the fact table, deduplicate to the entity column, and the result is exactly the population that has the behaviour the fact table records. The same shape recovers "users who have logged a session," "products that have been reviewed," "employees who have submitted an expense report" — wherever the question is "who shows up here."

You practiced using DISTINCT to derive a presence-list from a transactional table. "Which entities show up in this fact table" is the recurring question behind cohort-building, audience-derivation, and join-key sanity checks.

How you actually get good at SQL

Reading explains SQL. Writing it, over and over with instant feedback, is what makes you fluent.

That's the whole SQLMaxx loop: 600+ real problems, instant AI feedback, mastery you can actually see, and spaced review that won't let you forget.

A stack of SQL practice problem cards, the top card showing an employees table.
615 problems · 66 concepts

Real problems. Not toy examples.

615 hand-built problems spanning all 66 concepts, from basic SELECTs to window functions, built on real schemas and real business questions, the kind you'll actually get asked on the job. Enough reps to make SQL automatic.

A retro computer showing a SQL query marked correct with a green checkmark.
Instant AI feedback

Write a query. Know if it's right in one second.

No copying an answer and hoping it clicked. The AI grader checks your real query against real data, catches exactly what's wrong, and explains the fix in plain English, like a senior analyst reading over your shoulder on every problem.

A circular mastery progress dial filling from blue to green, the SQLMaxx diamond at its center.
Mastery tracking

Stop guessing whether you actually know it.

SQLMaxx tracks every concept and shows you what you've mastered and what's still shaky. Your skills fill in one concept at a time, so 'I think I get joins' becomes something you can prove.

A SQL query editor circled by a blue return arrow with a clock, scheduled to come back for review.
Spaced review

Learn it once. Keep it for good.

Most of what you learn this week fades by next week. So when a concept comes due for review, SQLMaxx hands you a fresh problem to solve from a blank editor, not a flashcard to re-read. A research-backed spaced-repetition algorithm (FSRS) times each return for right before you'd forget, so your SQL is still there months later, when the interview or the job actually needs it.

Practice, feedback, mastery, review. That's the loop that turns reading into real skill.

Start free

No account, no credit card. Start solving in under a minute.