N049-M4 Tier 4 · Advanced · medium ecommerce · Brightlane

Return every customer ID, their total order count, and the number of orders that are both delivered and have `total_amount` greater than `$200`

Part of FILTER Clause on Aggregates in SQL

The problem

Brightlane's revenue team is identifying customers with significant high-value delivery activity.

Write a query to return every customer ID, their total order count, and the number of orders that are both delivered and have total_amount greater than $200.

Assumptions:

  • The orders table has one row per order with a customer_id, a status, and a total_amount.
  • Each customer_id with at least one order should appear once.
  • For each customer, the total count covers every order. The high-value-delivered count covers only orders with both status = 'delivered' and total_amount greater than $200.

Output:

  • One row per customer with at least one order, with columns customer_id, total_orders, and high_value_delivered.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
SELECT
  customer_id,
  COUNT(*) AS total_orders,
  COUNT(*) FILTER (
    WHERE
      status = 'delivered'
      AND total_amount > 200
  ) AS high_value_delivered
FROM
  orders
GROUP BY
  customer_id

The shape

A single FILTER clause can carry a multi-condition boolean. FILTER (WHERE status = 'delivered' AND total_amount > 200) restricts the COUNT to orders that satisfy both rules at once, inside each customer's partition. One aggregate, one filter, two predicates joined by AND.

Clause by clause

  • SELECT customer_id, COUNT(*) AS total_orders, COUNT(*) FILTER (WHERE status = 'delivered' AND total_amount > 200) AS high_value_delivered returns the customer, their total order count, and the count of orders that are both delivered and above $200. The unfiltered total still covers every order in the partition; the filtered count only sees rows where both conditions hold.
  • FROM orders reads the order records.
  • GROUP BY customer_id partitions the rows per customer. The two counts evaluate inside each customer's partition.

Why one FILTER with AND and not two separate FILTERs

Two separate filters would produce two separate counts — delivered orders and high-value orders — not their intersection. The intersection is the goal here: only the orders that pass both rules. AND inside a single FILTER joins the two predicates so that the aggregate sees exactly the rows where both are true. A row that is delivered but cheap, or pricey but pending, drops out of the filtered count and stays in the unfiltered total.

The trap

FILTER (WHERE A AND B) excludes a row if either predicate is false or if either evaluates to NULL. For this problem the columns involved (status, total_amount) are populated on every order, so the NULL case does not surface in the data. The rule still binds: an AND inside a FILTER is three-valued, so any missing value on either side silently drops the row. When either predicate column can be NULL, decide explicitly whether NULL should count as a fail or be handled separately before relying on the AND.

You practiced FILTER (WHERE A AND B) — combine two conditions inside a single filter, restricting one aggregate to the intersection of both criteria.

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