N019-E1 Tier 2 · Core SQL · easy ecommerce · Brightlane

Return the product name and category name for every row in the combined view

Part of FULL OUTER JOIN in SQL

The problem

Brightlane's catalogue team needs a complete reconciliation of the product and category tables — both directions:

  • Every product appears, including products whose category does not resolve (category name will be NULL).
  • Every category appears, including categories with no products assigned (product name will be NULL).

Write a query to return the product name and category name for every row in the combined view.

Assumptions:

  • The products table contains every product in the catalogue.
  • The categories table contains every defined category.
  • Some products have a category_id that does not resolve to any category; some categories have no products assigned.

Output:

  • One row per matched product-category pair, plus one row per unmatched product (with category_name as NULL), plus one row per unmatched category (with product_name as NULL).
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
SELECT
  p.name AS product_name,
  cat.name AS category_name
FROM
  products p
  FULL OUTER JOIN categories cat ON p.category_id = cat.id

The shape

A FULL OUTER JOIN between products and categories keeps every row from both sides at once. Matched product-category pairs come out assembled; an orphan product comes out with category_name as NULL; an orphan category comes out with product_name as NULL. Three kinds of rows, one query.

Clause by clause

  • SELECT p.name AS product_name, cat.name AS category_name picks one column from each side of the join. On matched rows both values are real; on orphan rows the missing side's column is NULL, which is the signal the catalogue team reads as a gap.
  • FROM products p FULL OUTER JOIN categories cat ON p.category_id = cat.id is the reconciliation. The ON condition pairs a product with its category whenever category_id resolves; when it doesn't, the outer join keeps the row anyway and pads the other side with NULL. Because FULL makes that guarantee in both directions, a category with no products is preserved too.
  • No WHERE, no filter. The catalogue team asked for the combined view — matched plus both flavors of orphan — so every row the join produces belongs in the output.

You practiced a FULL OUTER JOIN to preserve every row from both tables. The recurring shape: when neither table has a privileged role and the question is "what's on each side, including the gaps," FULL OUTER JOIN is the only join type that surfaces both kinds of unmatched rows in a single result.

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