N014-M2 Tier 2 · Core SQL · medium ecommerce · Brightlane

Return each unique customer-status pairing and the number of orders that fall into it

Part of GROUP BY in SQL

The problem

Brightlane's support team is investigating order patterns and needs each customer's activity broken down by pipeline stage.

Write a query to return each unique customer-status pairing and the number of orders that fall into it.

Assumptions:

  • The orders table contains every order Brightlane has processed.
  • The output has one row for each unique combination of customer_id and status that appears in the data — a customer with orders in three different statuses contributes three rows.

Output:

  • One row per unique (customer_id, status) combination, with columns customer_id, status, and order_count.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

Run previews · Check grades

Write a query, then run it to see results here.

Worked solution Try it yourself first
Solution query
SELECT
  customer_id,
  status,
  COUNT(*) AS order_count
FROM
  orders
GROUP BY
  customer_id,
  status

The shape

Listing two columns in GROUP BY makes the unit of aggregation the unique pair, not the individual columns. Every distinct (customer_id, status) combination that appears in the data becomes its own bucket, and COUNT(*) runs once inside each one. Customer 8 with five delivered orders is one row in the output. Customer 8 with one shipped order would be a second row.

Clause by clause

  • SELECT customer_id, status, COUNT(*) AS order_count returns the two grouping columns and the per-pair count. Both customer_id and status are in the SELECT list because both appear in GROUP BY.
  • FROM orders reads the full order table as input.
  • GROUP BY customer_id, status partitions by the unique combination. The order in which the two columns are listed does not change the partitioning (the same pairs result either way); it only changes how a database tool might choose to sort or display the output.

Why this and not two queries

The support team could pull a per-customer count and a per-status count separately and try to reconstruct the breakdown by hand. A two-column GROUP BY returns the breakdown directly. Customer 38 shows up three times because they have orders in three different statuses, with delivered, pending, and cancelled each getting their own row. That is the shape an investigation into a single customer's pipeline actually needs.

The trap

Grouping by two columns produces more output rows than grouping by either one alone, often many more. A single-column GROUP BY status returns four rows. A single-column GROUP BY customer_id returns one row per customer. The two-column version returns one row per unique pair, which can be close to the row count of the source table on a high-cardinality combination. Check the result-set size against expectation, because a misread of the grouping unit is the easiest way to confuse a per-pair count with a per-customer count.

You practiced grouping by two columns at once. The rule is the same as one-column grouping: each unique combination of the listed columns forms its own group, and the aggregate runs once per combination.

How you actually get good at SQL

Reading explains SQL. Writing it, over and over with instant feedback, is what makes you fluent.

That's the whole SQLMaxx loop: 600+ real problems, instant AI feedback, mastery you can actually see, and spaced review that won't let you forget.

A stack of SQL practice problem cards, the top card showing an employees table.
615 problems · 66 concepts

Real problems. Not toy examples.

615 hand-built problems spanning all 66 concepts, from basic SELECTs to window functions, built on real schemas and real business questions, the kind you'll actually get asked on the job. Enough reps to make SQL automatic.

A retro computer showing a SQL query marked correct with a green checkmark.
Instant AI feedback

Write a query. Know if it's right in one second.

No copying an answer and hoping it clicked. The AI grader checks your real query against real data, catches exactly what's wrong, and explains the fix in plain English, like a senior analyst reading over your shoulder on every problem.

A circular mastery progress dial filling from blue to green, the SQLMaxx diamond at its center.
Mastery tracking

Stop guessing whether you actually know it.

SQLMaxx tracks every concept and shows you what you've mastered and what's still shaky. Your skills fill in one concept at a time, so 'I think I get joins' becomes something you can prove.

A SQL query editor circled by a blue return arrow with a clock, scheduled to come back for review.
Spaced review

Learn it once. Keep it for good.

Most of what you learn this week fades by next week. So when a concept comes due for review, SQLMaxx hands you a fresh problem to solve from a blank editor, not a flashcard to re-read. A research-backed spaced-repetition algorithm (FSRS) times each return for right before you'd forget, so your SQL is still there months later, when the interview or the job actually needs it.

Practice, feedback, mastery, review. That's the loop that turns reading into real skill.

Start free

No account, no credit card. Start solving in under a minute.