N015-E1 Tier 2 · Core SQL · easy ecommerce · Brightlane

Return the customer ID and order count for every customer with **more than three** orders on record

Part of HAVING in SQL

The problem

Brightlane's growth team is analysing repeat-purchase behaviour to build a loyalty programme.

Write a query to return the customer ID and order count for every customer with more than three orders on record.

Assumptions:

  • The orders table contains every order Brightlane has processed.
  • The threshold is on the per-customer count of orders — three orders does not qualify; four or more does.
  • The condition applies to the per-customer count, not to individual orders.

Output:

  • One row per qualifying customer, with columns customer_id and order_count.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
SELECT
  customer_id,
  COUNT(*) AS order_count
FROM
  orders
GROUP BY
  customer_id
HAVING
  COUNT(*) > 3

The shape

"More than three orders" is a per-customer condition, not a per-row one. GROUP BY customer_id builds the per-customer counts; HAVING COUNT(*) > 3 keeps only the groups that clear the threshold. The result is one row per qualifying customer — customer_id 17 with 5 orders, customer_id 51 with 4, and so on.

Clause by clause

  • SELECT customer_id, COUNT(*) AS order_count returns the grouping column with the count for each surviving group.
  • FROM orders is the source set: every order Brightlane has processed.
  • GROUP BY customer_id collapses the order rows into one row per customer. After this clause, each row in the working set represents one customer with their order count attached.
  • HAVING COUNT(*) > 3 filters those per-customer rows. Customers with three or fewer orders drop out; four or more survive.

Why this and not WHERE COUNT(*) > 3

WHERE runs before grouping happens, when the only thing in scope is an individual order row. At that point COUNT(*) has no meaning — there is no group yet to count, and PostgreSQL raises an error. HAVING runs after GROUP BY has produced the per-customer groups, which is the only moment the per-customer count exists.

You practiced filtering on an aggregate result with HAVING. The recurring rule: WHERE filters rows before they reach the aggregate; HAVING filters groups after the aggregate has computed — "more than three orders" is a group-level condition, so it belongs in HAVING.

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