N054-M1 Tier 4 · Advanced · medium ecommerce · Brightlane

Return every category ID, the total number of products in that category as `product_count`, and a JSON array of those product names as `product_names`

Part of JSONB Aggregation (jsonb_agg, json_build_object) in SQL

The problem

Brightlane's category management dashboard needs both a summary count and a structured product list per category.

Write a query to return every category ID, the total number of products in that category as product_count, and a JSON array of those product names as product_names.

Assumptions:

  • The products table has one row per product with an id, a name, and a category_id.
  • Each category_id with at least one product should appear once.
  • For each category, the product count is the number of products linked to that category_id. The product-names array contains every name value of those products (one element per product).

Output:

  • One row per category, with columns category_id, product_count, and product_names.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
SELECT
  category_id,
  COUNT(id) AS product_count,
  JSONB_AGG(name) AS product_names
FROM
  products
GROUP BY
  category_id

The shape

Two aggregates over the same GROUP BY partition do separate jobs: COUNT(id) returns a single integer per category, jsonb_agg(name) returns a JSON array per category. Both look at the same set of rows for each category and produce columns of different shapes, side by side in the same result row.

Clause by clause

  • SELECT category_id, COUNT(id) AS product_count, jsonb_agg(name) AS product_names returns three columns: the grouping key, a scalar count, and an array of names. COUNT(id) counts the rows in each group; jsonb_agg(name) collects the name values from those same rows into a JSONB array. Both aggregates evaluate against the same per-category set of input rows, just with different output types.
  • FROM products reads the product records.
  • GROUP BY category_id defines the per-category partition. For category 8 the partition has 5 products: COUNT(id) returns 5 and jsonb_agg(name) returns the five-element array ["Men's Slim Jeans", "Men's Polo Shirt", ...]. Same partition, two different summaries.

The trap

The natural assumption is that COUNT(id) and the length of the jsonb_agg(name) array must always be equal. They are equal here because every row has a non-null name and a non-null id. They are not equal in general: both aggregates skip NULL input values, so if name were nullable, the array could be shorter than the count. Match the column inside each aggregate to whatever the question is actually asking about.

You practiced combining a scalar aggregate (COUNT) with a structural aggregate (jsonb_agg) in the same GROUP BY query — both operate over the same partition and produce columns of different shapes.

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