N042-M2 Tier 4 · Advanced · medium ecommerce · Brightlane

Return every order's ID, customer ID, order amount, and that customer's previous order amount

Part of LAG and LEAD in SQL

The problem

Brightlane's finance team is building a calculation that needs a numeric prior-order value on every row, including a customer's first purchase. Where no prior order is on record, the team wants 0.00 rather than missing so downstream arithmetic continues uninterrupted.

Write a query to return every order's ID, customer ID, order amount, and that customer's previous order amount.

Assumptions:

  • A customer's previous order is the order with the largest ordered_at strictly before the current row's ordered_at, restricted to that customer.
  • For a customer's first order — where no prior order is on record — the previous-amount column should hold 0.00 instead of a missing value.
  • The final result is sorted by customer_id ascending, then by ordered_at ascending.

Output:

  • One row per order, with columns id, customer_id, total_amount, and prev_order_amount. Sorted by customer_id, then ordered_at.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
SELECT
  id,
  customer_id,
  total_amount,
  LAG(total_amount, 1, 0.00) OVER (
    PARTITION BY
      customer_id
    ORDER BY
      ordered_at
  ) AS prev_order_amount
FROM
  orders
ORDER BY
  customer_id,
  ordered_at

The shape

The third argument to LAG supplies a default value for rows that have no prior row to look back to. Writing LAG(total_amount, 1, 0.00) says "reach back one row; if that row does not exist, return 0.00 instead of NULL." The finance team's arithmetic gets a real number on every row, including each customer's first order.

Clause by clause

  • SELECT id, customer_id, total_amount, LAG(total_amount, 1, 0.00) OVER (PARTITION BY customer_id ORDER BY ordered_at) AS prev_order_amount returns the order's identifying columns and a guaranteed-numeric prior-order amount. The middle argument 1 is the offset (look back one row); the third argument 0.00 is the default that fires when the offset reaches outside the partition. The window definition is the same as the un-defaulted form: partition per customer, order chronologically.
  • FROM orders reads every order.
  • ORDER BY customer_id, ordered_at sorts the result for chronological reading.

Why the third argument and not a separate substitution step

LAG's three-argument signature folds the substitution into the window function itself, so the result type is consistent and no downstream step has to handle NULL. The default value is type-checked against total_amount at parse time, so LAG(total_amount, 1, 0.00) produces a numeric on every row. Reaching for a separate NULL-substitution function would not be wrong, but it would be a second step where the window function already offers a one-step solution that is purpose-built for exactly this case.

The trap

0.00 is a presentational sentinel, not a real prior-order amount. Any downstream calculation that aggregates prev_order_amount or treats it as a true previous purchase will count those zeros and skew the result. The right place for the default is in a report where the consumer needs a non-NULL value for display or for arithmetic that propagates NULL too aggressively. The wrong place is anywhere a SUM(prev_order_amount) or an average gets computed on the column; there, the default silently distorts the answer.

You practiced LAG(column, 1, default) — the third argument supplies a fallback when the offset reaches outside the partition, making the wrapper around LAG unnecessary.

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