N042-E3 Tier 4 · Advanced · easy ecommerce · Brightlane

Return every order's ID, order amount, and the preceding order amount in the global chronological sequence, sorted by `ordered_at`

Part of LAG and LEAD in SQL

The problem

Brightlane's logistics team reviews the complete order stream as a single chronological sequence — orders from every customer interleaved in time order. Each order should appear alongside the amount of the order placed immediately before it across the entire stream.

Write a query to return every order's ID, order amount, and the preceding order amount in the global chronological sequence, sorted by ordered_at.

Assumptions:

  • The preceding order is the order with the largest ordered_at strictly before the current row's ordered_at, across every customer.
  • For the very first order in the stream — where no preceding order is on record — the preceding-amount value is missing.
  • The final result is sorted by ordered_at ascending.

Output:

  • One row per order, with columns id, total_amount, and prev_order_amount. Sorted by ordered_at.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
SELECT
  id,
  total_amount,
  LAG(total_amount) OVER (
    ORDER BY
      ordered_at
  ) AS prev_order_amount
FROM
  orders
ORDER BY
  ordered_at

The shape

Dropping PARTITION BY collapses every order into a single global window, so LAG reaches back one position across the entire chronological stream regardless of which customer placed each order. The "previous" order is whoever placed an order immediately before, not the same customer's previous purchase.

Clause by clause

  • SELECT id, total_amount, LAG(total_amount) OVER (ORDER BY ordered_at) AS prev_order_amount returns each order's ID, amount, and the dollar amount of the order placed immediately before it in time. The window has no PARTITION BY, which means the entire orders table is one window; ORDER BY ordered_at sorts that single window chronologically; LAG looks back one row in that single sequence.
  • FROM orders reads every order.
  • ORDER BY ordered_at sorts the printed result chronologically.

Why drop PARTITION BY here and not keep it

The logistics team's question is about the full order stream as one interleaved sequence. Adding PARTITION BY customer_id would change the question to "what did this customer order previously," which is a different report. The absence of partitioning is load-bearing; it makes the lookup span across customers, not within them.

The trap

The very first order in the entire table (the earliest ordered_at across all customers) has no prior row anywhere in the data, so LAG returns NULL on that one row. Every other row has a predecessor, because the window covers every order. This is one NULL for the whole result, not one NULL per customer.

You practiced LAG(column) OVER (ORDER BY ...) without a PARTITION BY — the entire result is one window; the offset reaches across every record in the stream.

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