N058-H1 Tier 5 · Expert · hard ecommerce · Brightlane

Return every product that has appeared on at least one order line, with its `id`, name, the number of line items it appeared on, the total revenue it generated, and its share of total revenue across all products

Part of Multi-CTE Query Architecture in SQL

The problem

Scenario: Brightlane's buying team wants to understand each product's contribution to overall sales — both the absolute revenue and its share of the company-wide total.

Task: Write a query to return every product that has appeared on at least one order line, with its id, name, the number of line items it appeared on, the total revenue it generated, and its share of total revenue across all products.

Assumptions:

  • A line item's revenue is quantity multiplied by unit_price.
  • A product's revenue_share is its own total revenue divided by the combined revenue across every product in the result, expressed as a decimal between 0 and 1.
  • The result covers only products with at least one line item on record.

Output:

  • One row per qualifying product.
  • Columns in this order: product_id, product_name, line_item_count, revenue, revenue_share.
  • Sorted by revenue descending.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
WITH
  item_details AS (
    SELECT
      oi.product_id,
      p.name AS product_name,
      oi.quantity * oi.unit_price AS line_revenue
    FROM
      order_items oi
      JOIN products p ON oi.product_id = p.id
  ),
  product_summary AS (
    SELECT
      product_id,
      product_name,
      COUNT(*) AS line_item_count,
      SUM(line_revenue) AS revenue
    FROM
      item_details
    GROUP BY
      product_id,
      product_name
  ),
  product_shares AS (
    SELECT
      product_id,
      product_name,
      line_item_count,
      revenue,
      revenue / SUM(revenue) OVER () AS revenue_share
    FROM
      product_summary
  )
SELECT
  product_id,
  product_name,
  line_item_count,
  revenue,
  revenue_share
FROM
  product_shares
ORDER BY
  revenue DESC

The shape

Three CTEs that compute per-product revenue once, then layer a window-function denominator on top. The first names the per-line revenue, the second rolls up to per-product totals, and the third divides each product's total by SUM(revenue) OVER () — a window-function call with an empty OVER () that sums every row in the layer once and reuses that single number on every row. No second pass over the data, no scalar subquery, no second join.

Clause by clause

WITH item_details AS (
    SELECT oi.product_id, p.name AS product_name, oi.quantity * oi.unit_price AS line_revenue
    FROM order_items oi
    JOIN products p ON oi.product_id = p.id
)

The join attaches the product name to each line item and derives the row-level revenue. Both downstream layers depend on line_revenue existing, so it is named here once.

product_summary AS (
    SELECT product_id, product_name, COUNT(*) AS line_item_count, SUM(line_revenue) AS revenue
    FROM item_details
    GROUP BY product_id, product_name
)

GROUP BY product_id, product_name produces one row per product. COUNT(*) is the number of line items the product appeared on, SUM(line_revenue) is the product's total revenue. Crest Pro 14" leads with 11,994 across 6 line items.

product_shares AS (
    SELECT product_id, product_name, line_item_count, revenue,
           revenue / SUM(revenue) OVER () AS revenue_share
    FROM product_summary
)

SUM(revenue) OVER () is the window form: with an empty OVER (), the window covers every row in product_summary, so the sum is the combined revenue across every product. PostgreSQL computes that grand total once and reuses it on every row. Dividing each product's revenue by it gives the product's share as a decimal. Crest Pro 14" lands at 0.20, just over a fifth of total revenue.

  • SELECT product_id, product_name, line_item_count, revenue, revenue_share FROM product_shares ORDER BY revenue DESC returns the products from biggest to smallest contributor.

Why a window-function denominator and not a scalar subquery

The same share could be written as revenue / (SELECT SUM(revenue) FROM product_summary). The result matches. The window form is the architectural choice for two reasons. It keeps the denominator inside the layer where it is consumed, which means a reader following the chain top to bottom never has to look elsewhere to see where the grand total comes from. And when the partition rule later needs to change — say, share within a category instead of share across the catalog — the change is a single PARTITION BY clause inside the existing window, not a rewrite into a correlated subquery.

The trap

The OVER () is empty on purpose. Adding a PARTITION BY product_id (or any other column with one row per product in the layer) would partition the sum down to a single row per partition, and every product's denominator would equal its own revenue. Every revenue_share would come out as 1. The empty partition is what makes the window cover every row, which is what makes the denominator the grand total.

You practiced layering a window-function denominator over a totals CTE, so the per-product share divides each product's total by a single all-products total without a second pass.

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