N029-M1 Tier 3 · Intermediate · medium ecommerce · Brightlane

Return each customer alongside any cancelled order they have placed

Part of NULL Handling in Joins and Aggregates in SQL

The problem

Brightlane's operations team wants a list of every customer alongside their cancelled orders. Every customer must appear, including those without any cancelled order on record.

Write a query to return each customer alongside any cancelled order they have placed.

Assumptions:

  • The customers table has one row per customer with a name.
  • The orders table has one row per order, linked to a customer by customer_id and carrying a status. A cancelled order has status = 'cancelled'.
  • Customers with one or more cancelled orders contribute one row per cancelled order. Customers with no cancelled orders (including customers with no orders at all) contribute a single row with a missing cancelled_order_id.

Output:

  • One row per customer-cancelled-order pairing, plus one row per customer with no cancelled orders, with columns name and cancelled_order_id.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
SELECT
  c.name,
  o.id AS cancelled_order_id
FROM
  customers c
  LEFT JOIN orders o ON c.id = o.customer_id
  AND o.status = 'cancelled'

The shape

Moving status = 'cancelled' from the WHERE clause into the ON clause is what makes the LEFT JOIN actually preserve every customer. The condition becomes part of the matching rule rather than a post-join filter, so a customer with no cancelled order keeps their seat in the result with a missing cancelled_order_id.

Clause by clause

  • SELECT c.name, o.id AS cancelled_order_id returns each customer's name alongside the ID of the cancelled order attached on that row. When the join attached nothing, o.id is missing — which is exactly how the report signals "no cancelled order on record" for that customer.
  • FROM customers c LEFT JOIN orders o ON c.id = o.customer_id AND o.status = 'cancelled' pairs each customer with their cancelled orders only. The ON clause now has two conjoined conditions: the customer-to-order link, and the cancelled-status restriction. The join attaches an order only when both are true; otherwise the customer still appears, with every o.* column missing.

Why this and not WHERE o.status = 'cancelled'

A WHERE filter on a right-side column silently converts the LEFT JOIN back into an inner join. Customers with no orders at all would have every o.* column missing, including o.status, and NULL = 'cancelled' is not true — so those customers fail the filter and disappear. Customers with only non-cancelled orders are also dropped, because every one of their attached rows has o.status set to something other than 'cancelled'. The WHERE would leave only customers who had at least one cancelled order, which is not the population the operations team asked for.

The trap

The two placements look equivalent until you trace what happens to the unmatched rows. The ON condition runs during the matching step, so a failed match leaves a customer with a missing right-side and the row survives. The WHERE runs after the join produces its output, by which point the unmatched rows already exist and the missing-value comparison eliminates them. Same predicate, different timing, different result set.

You practiced moving a right-side condition into the ON clause — every left record stays, matching right rows attach, and non-matches yield a missing value rather than dropping the left row.

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