N024-E3 Tier 2 · Core SQL · easy hr · Helix Systems

Return the employee ID and salary amount for every above-average salary record

Part of Scalar Subqueries in SQL

The problem

Helix Systems' compensation team wants to flag every salary record that exceeds the company-wide average salary.

Write a query to return the employee ID and salary amount for every above-average salary record.

Assumptions:

  • The salaries table contains every salary record (current and historical).
  • The company-wide average is computed across every row in the salaries table.
  • An employee with multiple salary records may have some above and some below the average.

Output:

  • One row per above-average salary record, with columns employee_id and amount.
Schema · hr 4 tables
departments
id integer
name text
location text
budget numeric
salaries
id integer
employee_id integer
amount numeric
effective_date date
end_date? date
employees
id integer
name text
email text
department_id integer
manager_id? integer
hire_date date
title text
is_active boolean
job_history
id integer
employee_id integer
title text
department_id integer
start_date date
end_date? date

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Worked solution Try it yourself first
Solution query
SELECT
  employee_id,
  amount
FROM
  salaries
WHERE
  amount > (
    SELECT
      AVG(amount)
    FROM
      salaries
  )

The shape

Same structural pattern as the product-average filter, applied to Helix's salary records. (SELECT AVG(amount) FROM salaries) resolves to the company-wide average, and the outer WHERE keeps only the rows whose amount is strictly above that number.

Clause by clause

  • FROM salaries is the source: every salary record, including historical ones and multiple records per employee.
  • WHERE amount > (SELECT AVG(amount) FROM salaries) filters row by row. The subquery returns a single number — the average across every row in salaries. Each outer row's amount is compared against that number; rows at or below the average drop.
  • SELECT employee_id, amount returns the two identifying fields per qualifying record. An employee can appear multiple times in the result if more than one of their salary records sits above the company average — and disappear from rows where an earlier salary was below it. The filter operates per record, not per employee.

Why this and not a literal

A hardcoded threshold would go stale every time a new salary is recorded. The subquery recomputes the average on every run, so "above average" tracks the table as it changes — which is what the compensation team's flagging report needs.

You practiced the same scalar-subquery-in-WHERE shape against a different table. The pattern doesn't care about the domain — wherever the threshold is "the average / max / min of the column being filtered," the scalar subquery is the natural expression.

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