N024-M3 Tier 2 · Core SQL · medium analytics · Streamhub

Return the user ID, the conversion amount, and the combined total for every conversion record

Part of Scalar Subqueries in SQL

The problem

Streamhub's finance team wants to see each conversion record alongside the total revenue across all conversions.

Write a query to return the user ID, the conversion amount, and the combined total for every conversion record.

Assumptions:

  • The conversions table records each paid conversion.
  • The combined total (SUM(amount)) is computed over every row in conversions — the same value appears in the third column of every row.

Output:

  • One row per conversion record, with columns user_id, amount, and total_revenue.
Schema · analytics 5 tables
users
id integer
name text
email text
country text
plan text
signed_up_at timestamptz
is_active boolean
conversions
id integer
user_id integer
converted_at timestamptz
plan text
amount numeric
sessions
id integer
user_id integer
started_at timestamptz
ended_at? timestamptz
event_count integer
events
id integer
user_id integer
session_id? integer
event_type text
occurred_at timestamptz
properties? jsonb
periods
id integer
name text
start_month integer
end_month integer

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Worked solution Try it yourself first
Solution query
SELECT
  user_id,
  amount,
  (
    SELECT
      SUM(amount)
    FROM
      conversions
  ) AS total_revenue
FROM
  conversions

The shape

Same per-row-plus-overall pattern as the orders dashboard, applied to Streamhub's conversion revenue. (SELECT SUM(amount) FROM conversions) resolves to a single total — 8440 — and the outer query slots that figure next to every conversion record's own user_id and amount.

Clause by clause

  • SELECT user_id, amount returns the two row-level columns. These change with every output row.
  • (SELECT SUM(amount) FROM conversions) AS total_revenue is the scalar subquery. PostgreSQL runs the inner SELECT once, gets a single value (the combined total across every conversion record), and writes that value into every output row's third column. The subquery doesn't know which outer row is being emitted; it computes the same total regardless.
  • FROM conversions is the source. Both the outer query and the subquery read from conversions, but at different grains. The outer query reads every row once; the subquery collapses every row to one number.

Why this and not a join with a one-row summary table

A related shape some learners reach for: compute the total in a separate query, then "attach" it to every row through some join. The scalar-subquery form does the same job inline, with less structure. The single value is computed once at execution time and treated like a literal in the outer SELECT list. No join key, no auxiliary table — just an expression that resolves to a number, used wherever a number is valid.

You practiced the per-row-plus-overall pattern in a different domain. The structural shape (SELECT col1, col2, (SELECT AGG(col3) FROM table) FROM table) is what makes "this row's value, in context" reports possible without a second pass.

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