N023-E1 Tier 2 · Core SQL · easy analytics · Streamhub

Return the combined list of user IDs

Part of UNION, UNION ALL, INTERSECT, EXCEPT in SQL

The problem

Streamhub's growth team wants to gather every user ID that appears in either session records or conversion records into a single list for batch processing. Duplicates must be preserved — a user with three sessions and two conversions should produce five rows.

Write a query to return the combined list of user IDs.

Assumptions:

  • The sessions table records each session; user_id identifies the user.
  • The conversions table records each paid conversion; user_id identifies the user.
  • The output should not deduplicate — every record from both tables contributes one row.

Output:

  • One row per source record across both tables, with a single column user_id.
Schema · analytics 5 tables
users
id integer
name text
email text
country text
plan text
signed_up_at timestamptz
is_active boolean
conversions
id integer
user_id integer
converted_at timestamptz
plan text
amount numeric
sessions
id integer
user_id integer
started_at timestamptz
ended_at? timestamptz
event_count integer
events
id integer
user_id integer
session_id? integer
event_type text
occurred_at timestamptz
properties? jsonb
periods
id integer
name text
start_month integer
end_month integer

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Solution query
SELECT
  user_id
FROM
  sessions
UNION ALL
SELECT
  user_id
FROM
  conversions

The shape

UNION ALL concatenates the two result sets without inspecting them. Every user_id from sessions lands first, followed by every user_id from conversions — a user with three sessions and two conversions contributes five rows, which is the row-per-record shape the batch processor wants.

Clause by clause

  • SELECT user_id FROM sessions is the left query: one row per session, projecting just the user behind it.
  • UNION ALL is the set operator. The ALL keyword turns off deduplication, so PostgreSQL skips the sort-or-hash pass that UNION would add and just stacks the two result sets back-to-back. A user appearing multiple times in either input appears multiple times in the output.
  • SELECT user_id FROM conversions is the right query. The two sides must agree on column count and column type — one column of integers on each side here, which lines up.

Why this and not UNION

UNION would also combine the two result sets, but it adds a deduplication pass on top: PostgreSQL sorts or hashes the entire combined output and keeps each distinct row once. The batch processor wants every record represented; a user with three sessions and two conversions should produce five rows, not one. UNION would silently collapse them to one.

You practiced UNION ALL to stack two result sets without deduplication. The recurring rule: UNION ALL is the cheap concatenation; UNION adds a deduplication pass on top of it — pick UNION ALL whenever duplicates are wanted (or are known to be impossible).

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