N038-E2 Tier 3 · Intermediate · easy ecommerce · Brightlane

Return the ID and status of every order, plus the total number of orders on each row

Part of Window Functions Introduction (OVER, PARTITION BY) in SQL

The problem

Brightlane's operations report shows every order alongside the platform-wide order count for context.

Write a query to return the ID and status of every order, plus the total number of orders on each row.

Assumptions:

  • The orders table has one row per order with an id and a status.
  • The total order count is the number of records in orders. The same value should appear on every output row.

Output:

  • One row per order, with columns id, status, and total_orders.
Schema · ecommerce 5 tables
categories
id integer
name text
parent_id? integer
products
id integer
name text
category_id integer
price numeric
stock_qty integer
attributes? jsonb
order_items
id integer
order_id integer
product_id integer
quantity integer
unit_price numeric
customers
id integer
name text
email text
city? text
country text
created_at timestamptz
is_active boolean
orders
id integer
customer_id integer
ordered_at timestamptz
status text
total_amount numeric

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Solution query
SELECT
  id,
  status,
  COUNT(*) OVER () AS total_orders
FROM
  orders

The shape

COUNT(*) OVER () counts every row in the orders table and writes that single number onto every output row, next to each order's own id and status. The empty parentheses after OVER make the window the entire result.

Clause by clause

  • SELECT id, status returns each order's identifier and status, one row per order.
  • The window column is:
COUNT(*) OVER () AS total_orders

COUNT(*) counts the rows in its window. OVER () with empty parentheses defines that window as every row in the result, so the count is the total number of records in orders. The same value, 200 for this dataset, appears in total_orders on every row.

  • FROM orders reads every order. No filter, because the report counts the whole table.

Why this and not a plain COUNT(*) with GROUP BY

A standalone SELECT COUNT(*) FROM orders returns a single row holding the count. The operations report needs the count attached to every order, not in place of them. The window form keeps every row in the output and adds the aggregate as a side-by-side column, which is exactly the shape the report consumes.

You practiced COUNT(*) OVER () — compute a single record count across the entire result and replicate it onto every row.

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